Expansion of a helical spring

VP1.2.1.1
Expansion of a helical spring
Expansion of a helical spring

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Description

The experiment P1.2.1.1 shows that the extension s of a helical spring is directly proportional to the force Fs. Hooke’s law applies:

Components of equipment sets

1 35207  4  Helical spring 10 N/m LD
1 35208  4  Helical spring 25 N/m LD
1 34085  8  Weights, each 50 g, set of 6 LD
2 30121  8  Stand base MF LD
2 30127  4  Stand rod 50 cm, 10 mm Ø LD
1 30126  4  Stand rod 25 cm, 10 mm Ø LD
1 30125  4  Support block LD
1 31178  4  Tape measure 2 m / 1 mm LD
1 30129  4  Pointer, pair LD
1 340811  4  Plug-in axle LD

Experiment Instructions

PDF (Experiment description) PDF (Experiment description) P1.2.1.1 Expansion of a helical spring
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